2(h-6)+20=-40

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Solution for 2(h-6)+20=-40 equation: 



2(h-6)+20=-40

We move all terms to the left:

2(h-6)+20-(-40)=0

We add all the numbers together, and all the variables

2(h-6)+60=0

We multiply parentheses

2h-12+60=0

We add all the numbers together, and all the variables

2h+48=0

We move all terms containing h to the left, all other terms to the right

2h=-48

h=-48/2

h=-24

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