2(i+1)=3(i-5)

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Solution for 2(i+1)=3(i-5) equation:


Simplifying
2(i + 1) = 3(i + -5)

Reorder the terms:
2(1 + i) = 3(i + -5)
(1 * 2 + i * 2) = 3(i + -5)
(2 + 2i) = 3(i + -5)

Reorder the terms:
2 + 2i = 3(-5 + i)
2 + 2i = (-5 * 3 + i * 3)
2 + 2i = (-15 + 3i)

Solving
2 + 2i = -15 + 3i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-3i' to each side of the equation.
2 + 2i + -3i = -15 + 3i + -3i

Combine like terms: 2i + -3i = -1i
2 + -1i = -15 + 3i + -3i

Combine like terms: 3i + -3i = 0
2 + -1i = -15 + 0
2 + -1i = -15

Add '-2' to each side of the equation.
2 + -2 + -1i = -15 + -2

Combine like terms: 2 + -2 = 0
0 + -1i = -15 + -2
-1i = -15 + -2

Combine like terms: -15 + -2 = -17
-1i = -17

Divide each side by '-1'.
i = 17

Simplifying
i = 17

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