2(i+4)=4(i-2)

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Solution for 2(i+4)=4(i-2) equation:


Simplifying
2(i + 4) = 4(i + -2)

Reorder the terms:
2(4 + i) = 4(i + -2)
(4 * 2 + i * 2) = 4(i + -2)
(8 + 2i) = 4(i + -2)

Reorder the terms:
8 + 2i = 4(-2 + i)
8 + 2i = (-2 * 4 + i * 4)
8 + 2i = (-8 + 4i)

Solving
8 + 2i = -8 + 4i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-4i' to each side of the equation.
8 + 2i + -4i = -8 + 4i + -4i

Combine like terms: 2i + -4i = -2i
8 + -2i = -8 + 4i + -4i

Combine like terms: 4i + -4i = 0
8 + -2i = -8 + 0
8 + -2i = -8

Add '-8' to each side of the equation.
8 + -8 + -2i = -8 + -8

Combine like terms: 8 + -8 = 0
0 + -2i = -8 + -8
-2i = -8 + -8

Combine like terms: -8 + -8 = -16
-2i = -16

Divide each side by '-2'.
i = 8

Simplifying
i = 8

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