2(i-1)-7i=3(-3i+6)

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Solution for 2(i-1)-7i=3(-3i+6) equation: 



2(i-1)-7i=3(-3i+6)

We move all terms to the left:

2(i-1)-7i-(3(-3i+6))=0

We add all the numbers together, and all the variables

-7i+2(i-1)-(3(-3i+6))=0

We multiply parentheses

-7i+2i-(3(-3i+6))-2=0



We calculate terms in parentheses: -(3(-3i+6)), so:

3(-3i+6)

We multiply parentheses

-9i+18

Back to the equation:

-(-9i+18)



We add all the numbers together, and all the variables

-5i-(-9i+18)-2=0

We get rid of parentheses

-5i+9i-18-2=0

We add all the numbers together, and all the variables

4i-20=0

We move all terms containing i to the left, all other terms to the right

4i=20

i=20/4

i=5

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