2(j+3)+3(j-2)=10

Solution for 2(j+3)+3(j-2)=10 equation:

Simplifying
2(j + 3) + 3(j + -2) = 10

Reorder the terms:
2(3 + j) + 3(j + -2) = 10
(3 * 2 + j * 2) + 3(j + -2) = 10
(6 + 2j) + 3(j + -2) = 10

Reorder the terms:
6 + 2j + 3(-2 + j) = 10
6 + 2j + (-2 * 3 + j * 3) = 10
6 + 2j + (-6 + 3j) = 10

Reorder the terms:
6 + -6 + 2j + 3j = 10

Combine like terms: 6 + -6 = 0
0 + 2j + 3j = 10
2j + 3j = 10

Combine like terms: 2j + 3j = 5j
5j = 10

Solving
5j = 10

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Divide each side by '5'.
j = 2

Simplifying
j = 2