2(j+8)+5j-7=5(j-2)-3j-26

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Solution for 2(j+8)+5j-7=5(j-2)-3j-26 equation: 



2(j+8)+5j-7=5(j-2)-3j-26

We move all terms to the left:

2(j+8)+5j-7-(5(j-2)-3j-26)=0

We add all the numbers together, and all the variables

5j+2(j+8)-(5(j-2)-3j-26)-7=0

We multiply parentheses

5j+2j-(5(j-2)-3j-26)+16-7=0



We calculate terms in parentheses: -(5(j-2)-3j-26), so:

5(j-2)-3j-26

We add all the numbers together, and all the variables

-3j+5(j-2)-26

We multiply parentheses

-3j+5j-10-26

We add all the numbers together, and all the variables

2j-36

Back to the equation:

-(2j-36)



We add all the numbers together, and all the variables

7j-(2j-36)+9=0

We get rid of parentheses

7j-2j+36+9=0

We add all the numbers together, and all the variables

5j+45=0

We move all terms containing j to the left, all other terms to the right

5j=-45

j=-45/5

j=-9

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