2(j+8)=7(j-5)

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Solution for 2(j+8)=7(j-5) equation: 



2(j+8)=7(j-5)

We move all terms to the left:

2(j+8)-(7(j-5))=0

We multiply parentheses

2j-(7(j-5))+16=0



We calculate terms in parentheses: -(7(j-5)), so:

7(j-5)

We multiply parentheses

7j-35

Back to the equation:

-(7j-35)



We get rid of parentheses

2j-7j+35+16=0

We add all the numbers together, and all the variables

-5j+51=0

We move all terms containing j to the left, all other terms to the right

-5j=-51

j=-51/-5

j=10+1/5

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