2(j-1)=6(j+3)

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Solution for 2(j-1)=6(j+3) equation: 



2(j-1)=6(j+3)

We move all terms to the left:

2(j-1)-(6(j+3))=0

We multiply parentheses

2j-(6(j+3))-2=0



We calculate terms in parentheses: -(6(j+3)), so:

6(j+3)

We multiply parentheses

6j+18

Back to the equation:

-(6j+18)



We get rid of parentheses

2j-6j-18-2=0

We add all the numbers together, and all the variables

-4j-20=0

We move all terms containing j to the left, all other terms to the right

-4j=20

j=20/-4

j=-5

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