2(j-3)+J=3j-2j+6-j

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Solution for 2(j-3)+J=3j-2j+6-j equation: 



2(j-3)+=3j-2j+6-j

We move all terms to the left:

2(j-3)+-(3j-2j+6-j)=0

We add all the numbers together, and all the variables

2(j-3)-6+=0

We add all the numbers together, and all the variables

2(j-3)=0

We multiply parentheses

2j-6=0

We move all terms containing j to the left, all other terms to the right

2j=6

j=6/2

j=3

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