2(j-3)=-2+6

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Solution for 2(j-3)=-2+6 equation: 



2(j-3)=-2+6

We move all terms to the left:

2(j-3)-(-2+6)=0

We add all the numbers together, and all the variables

2(j-3)-4=0

We multiply parentheses

2j-6-4=0

We add all the numbers together, and all the variables

2j-10=0

We move all terms containing j to the left, all other terms to the right

2j=10

j=10/2

j=5

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