2(j-3)=9(6-3j)+10j

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Solution for 2(j-3)=9(6-3j)+10j equation:


2(j-3)=9(6-3j)+10j

We simplify the equation to the form, which is simple to understand
2(j-3)=9(6-3j)+10j

Reorder the terms in parentheses
+(+2j-6)=9*(6-3j)+10j

Remove unnecessary parentheses
+2j-6=+9+*(+6-3j+)+10j

Reorder the terms in parentheses
+2j-6=+(+54-27j)+10j

Remove unnecessary parentheses
+2j-6=+54-27j+10j

We move all terms containing j to the left and all other terms to the right.
+2j+27j-10j=+54+6

We simplify left and right side of the equation.
+19j=+60

We divide both sides of the equation by 19 to get j.
j=3.1578947368421

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