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2(k+1)=3(k-5)
We move all terms to the left:
2(k+1)-(3(k-5))=0
We multiply parentheses
2k-(3(k-5))+2=0
We calculate terms in parentheses: -(3(k-5)), so:We get rid of parentheses
3(k-5)
We multiply parentheses
3k-15
Back to the equation:
-(3k-15)
2k-3k+15+2=0
We add all the numbers together, and all the variables
-1k+17=0
We move all terms containing k to the left, all other terms to the right
-k=-17
k=-17/-1
k=+17
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