2(k+1)=3k-k+2

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Solution for 2(k+1)=3k-k+2 equation: 



2(k+1)=3k-k+2

We move all terms to the left:

2(k+1)-(3k-k+2)=0

We add all the numbers together, and all the variables

2(k+1)-(2k+2)=0

We multiply parentheses

2k-(2k+2)+2=0

We get rid of parentheses

2k-2k-2+2=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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