2(k+2)=4+2k

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Solution for 2(k+2)=4+2k equation: 



2(k+2)=4+2k

We move all terms to the left:

2(k+2)-(4+2k)=0

We add all the numbers together, and all the variables

2(k+2)-(2k+4)=0

We multiply parentheses

2k-(2k+4)+4=0

We get rid of parentheses

2k-2k-4+4=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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