2(k+3)=10-5

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Solution for 2(k+3)=10-5 equation: 



2(k+3)=10-5

We move all terms to the left:

2(k+3)-(10-5)=0

We add all the numbers together, and all the variables

2(k+3)-5=0

We multiply parentheses

2k+6-5=0

We add all the numbers together, and all the variables

2k+1=0

We move all terms containing k to the left, all other terms to the right

2k=-1

k=-1/2

k=-1/2

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