2(k+4)+5=2k-(k+5)

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Solution for 2(k+4)+5=2k-(k+5) equation: 



2(k+4)+5=2k-(k+5)

We move all terms to the left:

2(k+4)+5-(2k-(k+5))=0

We multiply parentheses

2k-(2k-(k+5))+8+5=0



We calculate terms in parentheses: -(2k-(k+5)), so:

2k-(k+5)

We get rid of parentheses

2k-k-5

We add all the numbers together, and all the variables

k-5

Back to the equation:

-(k-5)



We add all the numbers together, and all the variables

2k-(k-5)+13=0

We get rid of parentheses

2k-k+5+13=0

We add all the numbers together, and all the variables

k+18=0

We move all terms containing k to the left, all other terms to the right

k=-18

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