2(k+4)=3k-6

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Solution for 2(k+4)=3k-6 equation: 



2(k+4)=3k-6

We move all terms to the left:

2(k+4)-(3k-6)=0

We multiply parentheses

2k-(3k-6)+8=0

We get rid of parentheses

2k-3k+6+8=0

We add all the numbers together, and all the variables

-1k+14=0

We move all terms containing k to the left, all other terms to the right

-k=-14

k=-14/-1

k=+14

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