2(k+9)=6-(-2k-12)

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Solution for 2(k+9)=6-(-2k-12) equation: 



2(k+9)=6-(-2k-12)

We move all terms to the left:

2(k+9)-(6-(-2k-12))=0

We multiply parentheses

2k-(6-(-2k-12))+18=0



We calculate terms in parentheses: -(6-(-2k-12)), so:

6-(-2k-12)

determiningTheFunctionDomain
-(-2k-12)+6

We get rid of parentheses

2k+12+6

We add all the numbers together, and all the variables

2k+18

Back to the equation:

-(2k+18)



We get rid of parentheses

2k-2k-18+18=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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