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2(k-(2k+15)+1)=2(k+4)
We move all terms to the left:
2(k-(2k+15)+1)-(2(k+4))=0
We calculate terms in parentheses: -(2(k+4)), so:We get rid of parentheses
2(k+4)
We multiply parentheses
2k+8
Back to the equation:
-(2k+8)
2(k-(2k+15)+1)-2k-8=0
We add all the numbers together, and all the variables
-2k+2(k-(2k+15)+1)-8=0
We move all terms containing k to the left, all other terms to the right
-2k+2(k-(2k+15)+1)=8
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