2(k-(2k+18)+16)=2(k+2)

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Solution for 2(k-(2k+18)+16)=2(k+2) equation: 



2(k-(2k+18)+16)=2(k+2)

We move all terms to the left:

2(k-(2k+18)+16)-(2(k+2))=0



We calculate terms in parentheses: -(2(k+2)), so:

2(k+2)

We multiply parentheses

2k+4

Back to the equation:

-(2k+4)



We get rid of parentheses

2(k-(2k+18)+16)-2k-4=0

We add all the numbers together, and all the variables

-2k+2(k-(2k+18)+16)-4=0

We move all terms containing k to the left, all other terms to the right

-2k+2(k-(2k+18)+16)=4

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