2(k-(2k+7)+2)=2(k+5)

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Solution for 2(k-(2k+7)+2)=2(k+5) equation:



2(k-(2k+7)+2)=2(k+5)
We move all terms to the left:
2(k-(2k+7)+2)-(2(k+5))=0
We calculate terms in parentheses: -(2(k+5)), so:
2(k+5)
We multiply parentheses
2k+10
Back to the equation:
-(2k+10)
We get rid of parentheses
2(k-(2k+7)+2)-2k-10=0
We add all the numbers together, and all the variables
-2k+2(k-(2k+7)+2)-10=0
We move all terms containing k to the left, all other terms to the right
-2k+2(k-(2k+7)+2)=10

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