2(k-1)+5k=8(k+2)+3

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Solution for 2(k-1)+5k=8(k+2)+3 equation:



2(k-1)+5k=8(k+2)+3
We move all terms to the left:
2(k-1)+5k-(8(k+2)+3)=0
We add all the numbers together, and all the variables
5k+2(k-1)-(8(k+2)+3)=0
We multiply parentheses
5k+2k-(8(k+2)+3)-2=0
We calculate terms in parentheses: -(8(k+2)+3), so:
8(k+2)+3
We multiply parentheses
8k+16+3
We add all the numbers together, and all the variables
8k+19
Back to the equation:
-(8k+19)
We add all the numbers together, and all the variables
7k-(8k+19)-2=0
We get rid of parentheses
7k-8k-19-2=0
We add all the numbers together, and all the variables
-1k-21=0
We move all terms containing k to the left, all other terms to the right
-k=21
k=21/-1
k=-21

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