2(k-11)=-3k+8

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Solution for 2(k-11)=-3k+8 equation: 



2(k-11)=-3k+8

We move all terms to the left:

2(k-11)-(-3k+8)=0

We multiply parentheses

2k-(-3k+8)-22=0

We get rid of parentheses

2k+3k-8-22=0

We add all the numbers together, and all the variables

5k-30=0

We move all terms containing k to the left, all other terms to the right

5k=30

k=30/5

k=6

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