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2(k-12)-(-5)=11
We move all terms to the left:
2(k-12)-(-5)-(11)=0
determiningTheFunctionDomain 2(k-12)-11-(-5)=0
We add all the numbers together, and all the variables
2(k-12)-6=0
We multiply parentheses
2k-24-6=0
We add all the numbers together, and all the variables
2k-30=0
We move all terms containing k to the left, all other terms to the right
2k=30
k=30/2
k=15
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