2(k-4)=2(4k+8)

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Solution for 2(k-4)=2(4k+8) equation: 



2(k-4)=2(4k+8)

We move all terms to the left:

2(k-4)-(2(4k+8))=0

We multiply parentheses

2k-(2(4k+8))-8=0



We calculate terms in parentheses: -(2(4k+8)), so:

2(4k+8)

We multiply parentheses

8k+16

Back to the equation:

-(8k+16)



We get rid of parentheses

2k-8k-16-8=0

We add all the numbers together, and all the variables

-6k-24=0

We move all terms containing k to the left, all other terms to the right

-6k=24

k=24/-6

k=-4

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