2(k-5)/3=4(k+2)/5

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Solution for 2(k-5)/3=4(k+2)/5 equation: 


k in (-oo:+oo)

(2*(k-5))/3 = (4*(k+2))/5 // - (4*(k+2))/5

(2*(k-5))/3-((4*(k+2))/5) = 0

(2*(k-5))/3+(-4/5)*(k+2) = 0

(2*(k-5))/3-4/5*(k+2) = 0

(2*(k-5))/3+(-4/5*3*(k+2))/3 = 0

2*(k-5)-4/5*3*(k+2) = 0

-2/5*k-74/5 = 0

(-2/5*k-74/5)/3 = 0

(-2/5*k-74/5)/3 = 0 // * 3

-2/5*k-74/5 = 0

-2/5*k-74/5 = 0 // + 74/5

-2/5*k = 74/5 // : -2/5

k = 74/5/(-2/5)

k = -37

k = -37

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