2(k-6)+10=2(3k+5)

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Solution for 2(k-6)+10=2(3k+5) equation: 



2(k-6)+10=2(3k+5)

We move all terms to the left:

2(k-6)+10-(2(3k+5))=0

We multiply parentheses

2k-(2(3k+5))-12+10=0



We calculate terms in parentheses: -(2(3k+5)), so:

2(3k+5)

We multiply parentheses

6k+10

Back to the equation:

-(6k+10)



We add all the numbers together, and all the variables

2k-(6k+10)-2=0

We get rid of parentheses

2k-6k-10-2=0

We add all the numbers together, and all the variables

-4k-12=0

We move all terms containing k to the left, all other terms to the right

-4k=12

k=12/-4

k=-3

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