2(k-6)=4(k+2)

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Solution for 2(k-6)=4(k+2) equation: 



2(k-6)=4(k+2)

We move all terms to the left:

2(k-6)-(4(k+2))=0

We multiply parentheses

2k-(4(k+2))-12=0



We calculate terms in parentheses: -(4(k+2)), so:

4(k+2)

We multiply parentheses

4k+8

Back to the equation:

-(4k+8)



We get rid of parentheses

2k-4k-8-12=0

We add all the numbers together, and all the variables

-2k-20=0

We move all terms containing k to the left, all other terms to the right

-2k=20

k=20/-2

k=-10

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