2(k-9)=50-3(3k+1)

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Solution for 2(k-9)=50-3(3k+1) equation: 



2(k-9)=50-3(3k+1)

We move all terms to the left:

2(k-9)-(50-3(3k+1))=0

We multiply parentheses

2k-(50-3(3k+1))-18=0



We calculate terms in parentheses: -(50-3(3k+1)), so:

50-3(3k+1)

determiningTheFunctionDomain
-3(3k+1)+50

We multiply parentheses

-9k-3+50

We add all the numbers together, and all the variables

-9k+47

Back to the equation:

-(-9k+47)



We get rid of parentheses

2k+9k-47-18=0

We add all the numbers together, and all the variables

11k-65=0

We move all terms containing k to the left, all other terms to the right

11k=65

k=65/11

k=5+10/11

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