2(l+(l-12))=64

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Solution for 2(l+(l-12))=64 equation:


Simplifying
2(l + (l + -12)) = 64

Reorder the terms:
2(l + (-12 + l)) = 64

Remove parenthesis around (-12 + l)
2(l + -12 + l) = 64

Reorder the terms:
2(-12 + l + l) = 64

Combine like terms: l + l = 2l
2(-12 + 2l) = 64
(-12 * 2 + 2l * 2) = 64
(-24 + 4l) = 64

Solving
-24 + 4l = 64

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '24' to each side of the equation.
-24 + 24 + 4l = 64 + 24

Combine like terms: -24 + 24 = 0
0 + 4l = 64 + 24
4l = 64 + 24

Combine like terms: 64 + 24 = 88
4l = 88

Divide each side by '4'.
l = 22

Simplifying
l = 22

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