2(l+1)=3(9l-1)

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Solution for 2(l+1)=3(9l-1) equation: 



2(l+1)=3(9l-1)

We move all terms to the left:

2(l+1)-(3(9l-1))=0

We multiply parentheses

2l-(3(9l-1))+2=0



We calculate terms in parentheses: -(3(9l-1)), so:

3(9l-1)

We multiply parentheses

27l-3

Back to the equation:

-(27l-3)



We get rid of parentheses

2l-27l+3+2=0

We add all the numbers together, and all the variables

-25l+5=0

We move all terms containing l to the left, all other terms to the right

-25l=-5

l=-5/-25

l=1/5

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