2(l+1)=3(l-1)

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Solution for 2(l+1)=3(l-1) equation: 



2(l+1)=3(l-1)

We move all terms to the left:

2(l+1)-(3(l-1))=0

We multiply parentheses

2l-(3(l-1))+2=0



We calculate terms in parentheses: -(3(l-1)), so:

3(l-1)

We multiply parentheses

3l-3

Back to the equation:

-(3l-3)



We get rid of parentheses

2l-3l+3+2=0

We add all the numbers together, and all the variables

-1l+5=0

We move all terms containing l to the left, all other terms to the right

-l=-5

l=-5/-1

l=+5

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