2(l+3)=3(2l+1)

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Solution for 2(l+3)=3(2l+1) equation: 



2(l+3)=3(2l+1)

We move all terms to the left:

2(l+3)-(3(2l+1))=0

We multiply parentheses

2l-(3(2l+1))+6=0



We calculate terms in parentheses: -(3(2l+1)), so:

3(2l+1)

We multiply parentheses

6l+3

Back to the equation:

-(6l+3)



We get rid of parentheses

2l-6l-3+6=0

We add all the numbers together, and all the variables

-4l+3=0

We move all terms containing l to the left, all other terms to the right

-4l=-3

l=-3/-4

l=3/4

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