2(l+4)=3(2l+1)

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Solution for 2(l+4)=3(2l+1) equation:



2(l+4)=3(2l+1)
We move all terms to the left:
2(l+4)-(3(2l+1))=0
We multiply parentheses
2l-(3(2l+1))+8=0
We calculate terms in parentheses: -(3(2l+1)), so:
3(2l+1)
We multiply parentheses
6l+3
Back to the equation:
-(6l+3)
We get rid of parentheses
2l-6l-3+8=0
We add all the numbers together, and all the variables
-4l+5=0
We move all terms containing l to the left, all other terms to the right
-4l=-5
l=-5/-4
l=1+1/4

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