2(m)+4(4m+2)=108

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Solution for 2(m)+4(4m+2)=108 equation: 



2(m)+4(4m+2)=108

We move all terms to the left:

2(m)+4(4m+2)-(108)=0

We multiply parentheses

2m+16m+8-108=0

We add all the numbers together, and all the variables

18m-100=0

We move all terms containing m to the left, all other terms to the right

18m=100

m=100/18

m=5+5/9

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