2(m+1)-5(m-4)=28

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Solution for 2(m+1)-5(m-4)=28 equation: 



2(m+1)-5(m-4)=28

We move all terms to the left:

2(m+1)-5(m-4)-(28)=0

We multiply parentheses

2m-5m+2+20-28=0

We add all the numbers together, and all the variables

-3m-6=0

We move all terms containing m to the left, all other terms to the right

-3m=6

m=6/-3

m=-2

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