2(m+1)=3(4m-19)

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Solution for 2(m+1)=3(4m-19) equation: 



2(m+1)=3(4m-19)

We move all terms to the left:

2(m+1)-(3(4m-19))=0

We multiply parentheses

2m-(3(4m-19))+2=0



We calculate terms in parentheses: -(3(4m-19)), so:

3(4m-19)

We multiply parentheses

12m-57

Back to the equation:

-(12m-57)



We get rid of parentheses

2m-12m+57+2=0

We add all the numbers together, and all the variables

-10m+59=0

We move all terms containing m to the left, all other terms to the right

-10m=-59

m=-59/-10

m=5+9/10

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