2(m+1)=4(m-15)

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Solution for 2(m+1)=4(m-15) equation: 



2(m+1)=4(m-15)

We move all terms to the left:

2(m+1)-(4(m-15))=0

We multiply parentheses

2m-(4(m-15))+2=0



We calculate terms in parentheses: -(4(m-15)), so:

4(m-15)

We multiply parentheses

4m-60

Back to the equation:

-(4m-60)



We get rid of parentheses

2m-4m+60+2=0

We add all the numbers together, and all the variables

-2m+62=0

We move all terms containing m to the left, all other terms to the right

-2m=-62

m=-62/-2

m=+31

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