2(m+1)=S(3m-5)

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Solution for 2(m+1)=S(3m-5) equation:



2(m+1)=(3m-5)
We move all terms to the left:
2(m+1)-((3m-5))=0
We multiply parentheses
2m-((3m-5))+2=0
We calculate terms in parentheses: -((3m-5)), so:
(3m-5)
We get rid of parentheses
3m-5
Back to the equation:
-(3m-5)
We get rid of parentheses
2m-3m+5+2=0
We add all the numbers together, and all the variables
-1m+7=0
We move all terms containing m to the left, all other terms to the right
-m=-7
m=-7/-1
m=+7

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