2(m+3)-3m=7(m+1)+15

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Solution for 2(m+3)-3m=7(m+1)+15 equation: 



2(m+3)-3m=7(m+1)+15

We move all terms to the left:

2(m+3)-3m-(7(m+1)+15)=0

We add all the numbers together, and all the variables

-3m+2(m+3)-(7(m+1)+15)=0

We multiply parentheses

-3m+2m-(7(m+1)+15)+6=0



We calculate terms in parentheses: -(7(m+1)+15), so:

7(m+1)+15

We multiply parentheses

7m+7+15

We add all the numbers together, and all the variables

7m+22

Back to the equation:

-(7m+22)



We add all the numbers together, and all the variables

-1m-(7m+22)+6=0

We get rid of parentheses

-1m-7m-22+6=0

We add all the numbers together, and all the variables

-8m-16=0

We move all terms containing m to the left, all other terms to the right

-8m=16

m=16/-8

m=-2

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