2(m+3)-4(2m+1)=-3(2+m)

Solution for 2(m+3)-4(2m+1)=-3(2+m) equation:

2(m+3)-4(2m+1)=-3(2+m)

We move all terms to the left:

2(m+3)-4(2m+1)-(-3(2+m))=0

We add all the numbers together, and all the variables

2(m+3)-4(2m+1)-(-3(m+2))=0

We multiply parentheses

2m-8m-(-3(m+2))+6-4=0


We calculate terms in parentheses: -(-3(m+2)), so:

-3(m+2)

We multiply parentheses

-3m-6

Back to the equation:

-(-3m-6)


We add all the numbers together, and all the variables

-6m-(-3m-6)+2=0

We get rid of parentheses

-6m+3m+6+2=0

We add all the numbers together, and all the variables

-3m+8=0

We move all terms containing m to the left, all other terms to the right

-3m=-8

m=-8/-3

m=2+2/3