2(m+3)-4m=5+2(m-1)

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Solution for 2(m+3)-4m=5+2(m-1) equation: 



2(m+3)-4m=5+2(m-1)

We move all terms to the left:

2(m+3)-4m-(5+2(m-1))=0

We add all the numbers together, and all the variables

-4m+2(m+3)-(5+2(m-1))=0

We multiply parentheses

-4m+2m-(5+2(m-1))+6=0



We calculate terms in parentheses: -(5+2(m-1)), so:

5+2(m-1)

determiningTheFunctionDomain
2(m-1)+5

We multiply parentheses

2m-2+5

We add all the numbers together, and all the variables

2m+3

Back to the equation:

-(2m+3)



We add all the numbers together, and all the variables

-2m-(2m+3)+6=0

We get rid of parentheses

-2m-2m-3+6=0

We add all the numbers together, and all the variables

-4m+3=0

We move all terms containing m to the left, all other terms to the right

-4m=-3

m=-3/-4

m=3/4

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