2(m+3)=3(2+m)

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Solution for 2(m+3)=3(2+m) equation: 



2(m+3)=3(2+m)

We move all terms to the left:

2(m+3)-(3(2+m))=0

We add all the numbers together, and all the variables

2(m+3)-(3(m+2))=0

We multiply parentheses

2m-(3(m+2))+6=0



We calculate terms in parentheses: -(3(m+2)), so:

3(m+2)

We multiply parentheses

3m+6

Back to the equation:

-(3m+6)



We get rid of parentheses

2m-3m-6+6=0

We add all the numbers together, and all the variables

-m=0

m=0/-1

m=0

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