2(m+3)=3(m-2)

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Solution for 2(m+3)=3(m-2) equation: 



2(m+3)=3(m-2)

We move all terms to the left:

2(m+3)-(3(m-2))=0

We multiply parentheses

2m-(3(m-2))+6=0



We calculate terms in parentheses: -(3(m-2)), so:

3(m-2)

We multiply parentheses

3m-6

Back to the equation:

-(3m-6)



We get rid of parentheses

2m-3m+6+6=0

We add all the numbers together, and all the variables

-1m+12=0

We move all terms containing m to the left, all other terms to the right

-m=-12

m=-12/-1

m=+12

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