2(m+3/2)=2(m-5)

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Solution for 2(m+3/2)=2(m-5) equation: 



2(m+3/2)=2(m-5)

We move all terms to the left:

2(m+3/2)-(2(m-5))=0

We add all the numbers together, and all the variables

2(+m+3/2)-(2(m-5))=0

We multiply parentheses

2m-(2(m-5))+3/2*2=0

We multiply all the terms by the denominator


2m*2*2-((2(m-5)))*2*2+3=0

Wy multiply elements

8m*2-((2(m-5)))*2*2+3=0

Wy multiply elements

16m-((2(m-5)))*2*2+3=0

We move all terms containing m to the left, all other terms to the right

16m-((2(m-5)))*2*2=-3

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