2(m+4)-3m=8(m-1)

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Solution for 2(m+4)-3m=8(m-1) equation:



2(m+4)-3m=8(m-1)
We move all terms to the left:
2(m+4)-3m-(8(m-1))=0
We add all the numbers together, and all the variables
-3m+2(m+4)-(8(m-1))=0
We multiply parentheses
-3m+2m-(8(m-1))+8=0
We calculate terms in parentheses: -(8(m-1)), so:
8(m-1)
We multiply parentheses
8m-8
Back to the equation:
-(8m-8)
We add all the numbers together, and all the variables
-1m-(8m-8)+8=0
We get rid of parentheses
-1m-8m+8+8=0
We add all the numbers together, and all the variables
-9m+16=0
We move all terms containing m to the left, all other terms to the right
-9m=-16
m=-16/-9
m=1+7/9

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