2(m+4)-6m=40

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Solution for 2(m+4)-6m=40 equation: 



2(m+4)-6m=40

We move all terms to the left:

2(m+4)-6m-(40)=0

We add all the numbers together, and all the variables

-6m+2(m+4)-40=0

We multiply parentheses

-6m+2m+8-40=0

We add all the numbers together, and all the variables

-4m-32=0

We move all terms containing m to the left, all other terms to the right

-4m=32

m=32/-4

m=-8

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