2(m+5)(m+5)=0

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Solution for 2(m+5)(m+5)=0 equation: 



2(m+5)(m+5)=0

We multiply parentheses ..

2(+m^2+5m+5m+25)=0

We multiply parentheses

2m^2+10m+10m+50=0

We add all the numbers together, and all the variables

2m^2+20m+50=0

a = 2; b = 20; c = +50;
Δ = b2-4ac
Δ = 202-4·2·50
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{-20}{4}=-5$

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