2(m-(2m+10)+7)=2(m+3)

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Solution for 2(m-(2m+10)+7)=2(m+3) equation: 



2(m-(2m+10)+7)=2(m+3)

We move all terms to the left:

2(m-(2m+10)+7)-(2(m+3))=0



We calculate terms in parentheses: -(2(m+3)), so:

2(m+3)

We multiply parentheses

2m+6

Back to the equation:

-(2m+6)



We get rid of parentheses

2(m-(2m+10)+7)-2m-6=0

We add all the numbers together, and all the variables

-2m+2(m-(2m+10)+7)-6=0

We move all terms containing m to the left, all other terms to the right

-2m+2(m-(2m+10)+7)=6

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