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2(m-1)+5/2m=2/3(m+3)
We move all terms to the left:
2(m-1)+5/2m-(2/3(m+3))=0
Domain of the equation: 2m!=0
m!=0/2
m!=0
m∈R
Domain of the equation: 3(m+3))!=0We multiply parentheses
m∈R
2m+5/2m-(2/3(m+3))-2=0
We calculate fractions
2m+(15mm/(6m^2m+(-(2*2m)/(6m^2m-2=0
We can not solve this equation
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